Math, asked by santheesh40, 1 year ago

sin A = 3/5,0<A<π\2 and cos B = -12/13,π <B< 3π\2
following: tan (A-B)​

Answers

Answered by Nsranjan
1

Answer:

as, tanA=3/4

tanB=-5/12

tan(A-B) =(3/4 +5/12) ÷1-(3/4×-5/12)

=56/63

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