Question

Sin A =3/5 , Cos B=12/13 then , (tan A-tanB)/1+tanA . tanB=?​

Answer 1

Answer:

Step-by-step explanation:

Sin a=3/5

Therefore cos a = 4/5(by using 3-4-5 right triangle)

Similarly sin b=5/13 ( 5-12-13 right triangle)

Tan a=sin a/cos a =3/4

Tan b= sin b/cos b= 5/12

Now (tan a-tan b)/1+tan a.tan b

= (3/5 - 5/12)/1+3*5/4*12

Solve it further