Sin A 3/5 then find value of Sin 2A
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Answered by
83
You need to apply the double angle formula for the sine:
sin(2A) = 2sin(A)cos(A)
Since sin(A) = 3/5:
sin(2A) = 2*(4/5)*cos(A) = (8/5)cos(A)
To find cos(A), use the Pythagorean identity:
sin2(A) + cos2(A) = 1
cos2(A) = 1 - sin2(A)
cos2(A) = 1 - (4/5)2
cos2(a) = 9/25
√cos2(A) = √(9/25)
cos(A) = ±3/5
So:
sin(2A) = (8/5)*(±3/5) = ±24/25
this is just example just by yourself
sin(2A) = 2sin(A)cos(A)
Since sin(A) = 3/5:
sin(2A) = 2*(4/5)*cos(A) = (8/5)cos(A)
To find cos(A), use the Pythagorean identity:
sin2(A) + cos2(A) = 1
cos2(A) = 1 - sin2(A)
cos2(A) = 1 - (4/5)2
cos2(a) = 9/25
√cos2(A) = √(9/25)
cos(A) = ±3/5
So:
sin(2A) = (8/5)*(±3/5) = ±24/25
this is just example just by yourself
Answered by
0
Answer:
24/25
Step-by-step explanation:
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