Question

Sin A = √3 over 2 and cos B = √3 over 2
find the value of : (1) Sin 2 b + Cos 2 A
(2) 4 Sin 3 A _ 3 Sin A​

Answer 1

Answer:

Given

sinA=

2

3

sinA= sin60

A= 60

∘

cosB=

2

3

cosB= cos30

B= 30

∘

Now,

1+tanAtanB

tanA−tanB

=

1+tan60tan30

tan60−tan30

=

1+

3

(

3

1

)

3

−

3

1

=

2

3

2

=

3

1

Step-by-step explanation:

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