Question

Sin A = 6/10 find the value of cos A + tanA
Pls answer

Answer 1

Answer:

31/20

Step-by-step explanation:

sinA = 6/10

→ height/hypotenuse = 6/10

Let height be 6 and hypotenuse be 10.

Using Pythagoras theorem,

base² + 6² = 10² → base = 8

Therefore, cosA = base/hypotenuse

cosA = 8/10

Similarly, tanA = height/base

tanA = 6/8

Hence,

cosA + tanA = 8/10 + 6/8

= (64 + 60)/80

= 124/80

= 31/20

Answer 2

Answer:

Step-by-step explanation:

SinA=6/10

Hypotenuse=10

Opposite side=6

Adjacent side=Y

By Pythagoras theorom,

10^2=6^2+y^2

100=36+y^2

64=y^2

y=8

CosA=adjacent side/hypotenuse

=8/10=4/5

cosA=4/5

tanA=opposite side/adjacent side

tanA=6/4

tanA=3/2

Thanks