Question

sin A =a/b then find the value of secA +tanA in terms of a and b with full explanation.l will mark his answer as brainliest​

Answer 1

This explains the sum:

Answer 2

Answer:

secA +tanA=√(b+a) /(b-a)

Step-by-step explanation:

Given, sinA=a/b

we know, sin^2 A + cos^2 A=1

=> cos^2 A =1 - sin^2 A

=> cosA = √(1-sin^2 A)

=> cosA = √(1- a^2/b^2)

=> cosA = √(b^2 - a^2) /b

Now, secA + tanA

= 1/cosA + sinA/cosA

= (1+sinA) /cosA

= (1+ a/b) /√(b^2 - a^2) /b

= b(b+a) /b√(b+a) (b-a)

= √(b+a) /(b-a)