Question

sin A+B = 0° and sinA-B = 1/2​

Answer 1

Answer:

$sin(a + b) = 0 \: \: \: and \: \sin(a - b) = \frac{1}{2 }$

$\sin(a + b) = \sin(0) \: \: \: and \: \sin(a - b) = \sin(30)$

$a + b = 0 and \: a - b = 30 \\ now \:a dding \: the \: equatins \: we \: get \\ 2a = 30 \\ a = 15 \\ b = - 15$

Step-by-step explanation:

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