Question

Sin(A-B)=1/√10,cos(A+B)=2/√29 find tan2A where A And B lie btw 0 to pie by 4

Answer 1

Answer:

17

Step-by-step explanation:

cos(A-B) = √(1)² -1/(√10)² = 3/√10

sin(A+B) = √(1)² - (2/√29)² = 5/√29

using both ,

tan (A+B) = 5/2

tan(A-B) = 1/3

Now,

tan2A = tan((A+B)+(A-B))

= (5/2 + 1/3)/1 - (5/2)(1/3)

= 17 (ans.)

Answer 2

your answer tan2A is 17....