Question

sin(A-B)=1/2 and cos(A+B)=1/2,00<A+B< 90 find the A and B​

Answer 1

Answer:

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Answer 2

Answer:

A = 45°, B = 15°

Step-by-step explanation:

sin(A-B) = 1/2, cos(A+B) = 1/2

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°45°- B = 30°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°45°- B = 30°-B = 30°-45°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°45°- B = 30°-B = 30°-45°-B = -15°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°45°- B = 30°-B = 30°-45°-B = -15°B = 15°

sin(A-B) = 1/2, cos(A+B) = 1/2sin(A-B) = sin30°cos(A+B) = cos60°A-B = 30°---- eq. (I)A+B = 60°---- eq. (II)On adding eq. (I) and eq.(II);2A = 90°A = 45°Putting this value in eq. (I);A-B = 30°45°- B = 30°-B = 30°-45°-B = -15°B = 15°Hope this helps.