Question

sin(A-B)=1/2 , cos(A+B)=1/2 find A and B​

Answer 1

Answer:

sin ( A-B) = 1/2

sin( A-B) = sin 30°

A-B = 30 -------(i)

cos ( A+B) = 1/2

cos (A+B) = cos 60°

A+B = 60-----------(ii)

from (i) and (ii)

A+B = 60

A-B = 30

________

2A. = 90

A. = 45

putting the value in of A in equation (i)

A-B= 30

45 - B = 30

B = 15

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Answer 2

$\huge\green{\boxed{ANSWER}}$

sin(A-B)=1/2

sin(A-B)= sin30°

By comparing

A-B = 30°____________(1)

Also

cos(A+B)=1/2

cos(A+B) =cos60°

By comparing

A+B =60°_____________(2)

Now,

Adding eq(1)and eq(2)

A-B +A+B =30°+60°

2A =90°

A=45°

Put A = 90° in eq (2)

We get

B=45°

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