sin(A-B)=1/2,cos(A+B)=1/2,then find A and B
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Answered by
7
Given: sin (A+B)=1/2
cos (A+B)=1/2
We know that Sin (A-B)=sin30 degree
so, A-B=30- - - - - >1
We know that cos (A+B)=1/2
cos(A+B)=cos60 degree
A+B=60- - - - - - - - >2
adding 1 & 2,
we get 2A=90 degree
A=45 degrees.
Substituting A value in 1,
We get B=15 degrees.
HOPE IT HELPS YOU ☆☆☆
cos (A+B)=1/2
We know that Sin (A-B)=sin30 degree
so, A-B=30- - - - - >1
We know that cos (A+B)=1/2
cos(A+B)=cos60 degree
A+B=60- - - - - - - - >2
adding 1 & 2,
we get 2A=90 degree
A=45 degrees.
Substituting A value in 1,
We get B=15 degrees.
HOPE IT HELPS YOU ☆☆☆
Answered by
7
Heya user !!!
Here's the answer you are looking for
sin(A - B) = 1/2
We know sin 30 = 1/2
So, A - B = 30 ———— (1)
Also, cos (A + B) = 1/2
We know cos 60 = 1/2
So, A + B = 60 ———— (2)
Adding (1) and (2), we get,
2A = 90
A = 90/2 = 45
A + B = 60
45 + B = 60
B = 60 - 45 = 15
Therefore, A is 45° and B is 15°
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
sin(A - B) = 1/2
We know sin 30 = 1/2
So, A - B = 30 ———— (1)
Also, cos (A + B) = 1/2
We know cos 60 = 1/2
So, A + B = 60 ———— (2)
Adding (1) and (2), we get,
2A = 90
A = 90/2 = 45
A + B = 60
45 + B = 60
B = 60 - 45 = 15
Therefore, A is 45° and B is 15°
★★ HOPE THAT HELPS ☺️ ★★
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