Question

sin (A+B) = 1, & sin (A-B & sin (A-B) = 1 ; Les? /B=2​

Answer 1

★given:-

• sin (A+B) = 1

• sin (A-B) = 1

★find:-

• value of A and B

★solution:-

• $\implies \red{ \sin(A+B) = 1}$

we know that

• $\implies \star \pink{ \sin 90 \degree = 1}$

• $\implies \red{ \sin(A + B) = \sin90 \degree }$

do comparison

• $\implies \red{ A+B = 90 } - - - (1)$

similarly

$\implies \purple{ \sin(A - B) = 1}$

$\implies \purple{ \sin(A - B) = \sin90 \degree }$

$\implies \purple{A - B = 90 } - - - (2)$

addition of EQ 1 and 2

$\implies \: \red{A+B} + \purple{A - B} = \red{90 } + \purple{90}$

$\implies \pink{2A = 180 \degree} \\ \\ \\ \implies \pink{A = \frac{180}{2} } \\ \\ \\ \implies \pink{A = 90}$

A value put on EQ 1

$\implies \green{90 + B = 90} \\ \\ \\ \implies \green{B = 90 - 90 = 0}$

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answer

$\star\pink{A = 90}$

$\star\green{B = 0}$

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I hope it helps you