Question

sin (A+B)=1 & tan (A-B) =1/root 3 find tanA+cotB,secA-cosecB

Answer 1

HEY DEAR ... ✌️

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Here's , ur answer :-


Sec(A+B)=1                [∵ sin 90°=1 ]

 ⇒(A+B)=90°       ............(1)


tan(A-B)=1/√3          [∵ tan 30°=1/√3 ]

⇒(A-B)=30°        .............(2)

 Solving (1) and (2),we get,

A=60°
B=30°


1) tan A + cot B

tan 60°+ cot 30°
= √3 + √3
= 2√3


2) sec A - cosec B

sec 60° - cosec 30°
= 2-2
= 0


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HOPE , IT HELPS ... ✌️

Answer 2

$2 \sqrt{3} \\ 0$