sin(A+B) = 1 and cos(A - B) = 1, then A equals to?
(1) B/2
(2) -B
(3) B
With steps
TheIncorporealKlaus:
A=B=45°
Answers
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sin (A+B) =sin 90°
(A+B)= 90°------(1)
cos(A-B) =cos 0°
(A-B) =0° -------(2)
A=B ----(3)
PUT (3) IN (1)
2B=90
B=45°
SO ANSWER IS (3) B
(A+B)= 90°------(1)
cos(A-B) =cos 0°
(A-B) =0° -------(2)
A=B ----(3)
PUT (3) IN (1)
2B=90
B=45°
SO ANSWER IS (3) B
Not the only method ya can apply here, but hey your answer is correct!
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