Question

Sin(A+B)=1 and Cos(A-B) =√3/2. Find A and B

Answer 1

I hope this useful for you.
mark as brainliest.

Answer 2

hey here is ur ans .....


sin( A+B ) = 1
=>sin(A+B ) = sin 90°
=> A+B = 90 .....(i )

And

$\cos(a - b ) = \sqrt{3} \div 2$
$\cos(a - b) = \cos(30)$
a - b = 30 ....(ii)

adding both eq

a + b = 90
a - b = 30
________
2a = 120
a = 60


=> a + b = 90
=> 60 + b = 90
=> b = 30



hope it will help uh ..
nd plz mark as brainliest ..