Question

Sin(A+B) = 1 and Cos(A-B) = √3/2 then find the value of A.

Answer 1

Step-by-step explanation:

see the attachment given

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Answer 2

Answer:

Sin(A+B)=1,

we know that,

Sin 90°=1 then

Sin(A+B)=sin90

then,

A+B=90___1st eq

Cos(A-B)=√3/2(GIVEN)

we know that

Cos 30=√3/2

so,

Cos(A-B)=Cos 30

then

A-B=30__2nd eq

from 1st and 2nd equation

A+B=90

A-B=30

______

2A=120

A=60

then,

by substituting Ain 1st eq

A+B=90

60+B=90

then,

B=30

therefore ,

A=60,B=30