Question

Sin (A+B) =1 and Cos B = 1/2 then find <A and < B (0°<A+B_< 90°)​

Answer 1

Answer:

Cos B = 1/2 =Cos 60°

∴     B = 60°

Sin (A+B) = 1 = Sin 90°

∴    A+B = 90°

A+60° = 90°

A  = 90° - 60°

A  = 30°