sin (A + B)=1 and sin (A-B) =1212 ; 0° <A+B < 90°; A >B. Find A and B.
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Answer:
We know that
Sin (A+B)=1
A+B=90 equation 1
Sin(A-B)=1\2
A-B=30 equation 2
Solving eq.1and2
A+B=90
A=90-B eq.3
Put the value of A in eq.2
90-B-B=30
-2B =30-90
-2B=-60
B=30
Put the value of B in eq.3
A=90-30
A=60
Hence proved
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