Math, asked by iqra83308, 3 months ago

sin (A + B)=1 and sin (A-B) =1212 ; 0° <A+B < 90°; A >B. Find A and B.​

Answers

Answered by Anonymous
7

Answer:

Answer:

We know that

Sin (A+B)=1

A+B=90 equation 1

Sin(A-B)=1\2

A-B=30 equation 2

Solving eq.1and2

A+B=90

A=90-B eq.3

Put the value of A in eq.2

90-B-B=30

-2B =30-90

-2B=-60

B=30

Put the value of B in eq.3

A=90-30

A=60

Hence proved

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