Question

sin(a+b)=1 and tan(a-b)=1/√3,find a and b​

Answer 1

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Answer 2

$\huge \bold{hey \: there}$

sin(A+B)=1

sin(A+B)=sin90°

Cancelling sin from both sides,

A+B=90°-----(1)

tan(A-B)=1/√3

tan(A-B)=tan30°

Cancelling tan from both sides,

A-B=30°-----(2)

Adding (1) and (2),

2A=120°

A=60°

Substituting this value in (1),

60+B=90

B=90-60

B=30°

Hence, A=60° and B=30°.