Question

sin (a+b) =1 cos(a-b)=root 3/2 find a and b​

Answer 1

Answer:

a = 60°, b = 30°

Step-by-step explanation:

Please check the attachment as it has the step by step explanation.

Answer 2

Answer :

a = 60° , b = 30°

Solution :

• Given : sin(a+b) = 1 , cos(a-b) = √3/2
• To find : a , b = ?

We have ;

=> sin(a + b) = 1

=> sin(a + b) = sin90°

=> a + b = 90° -------(1)

Also ,

=> cos(a - b) = √3/2

=> cos(a - b) = cos30°

=> a - b = 30° ------(2)

Now ,

Adding eq-(1) and (2) , we have ;

=> a + b + a - b = 90° + 30°

=> 2a = 120°

=> a = 120°/2

=> a = 60°

Now ,

Putting a = 60° in eq-(1) , we get ;

=> a + b = 90°

=> 60° + b = 90°

=> b = 90° - 60°

=> b = 30°

Hence ,

a = 60° , b = 30°