Question

sin(A+B)=1 tan(A-B) =1/√3 A=B then find the vaues of A and B​

Answer 1

Step-by-step explanation:

Sec(A+B)=1                [∵ sin 90°=1 ]

⇒(A+B)=90°       ............(1)

(1)tan(A-B)=1/√3          [∵ tan 30°=1/√3 ]

    ⇒(A-B)=30°        .............(2)

Solving (1) and (2),we get,

A=60°B=30°

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Answer 2

Answer:

sin( A+B )= 1

sin(A+B)= sin 90

A+B =90

tan (A-B )= 30

tan(A-B) = tan 30

A-B =30

by solving the equations

we get A=60

and B= 30