Question

sin(a-b)=√3/2 and tan(a-b) =√3 find and b​

Answer 1

a-b=60⁰

a-b =30⁰

- += -

-2a =30⁰

a=30⁰/-2

a=-15⁰

put the value of in eq 1

-15-b=60⁰

-b=60⁰+15

-b=75⁰

b=-75⁰

Answer 2

Step-by-step explanation:

Your question is wrong somehow or incomplete!! because if we talk about

sin(a-b)=√3/2 then we get a-b =60 degree

and if consider tan(a-b) =√3 then we get again a-b=60 degree

so if we solve that then we get

a=60 degree and b=0 degree if this is answer than you are right!!