Question

Sin (a+b ) = √3/2 qnd cos (a+b)= 1 find the value of A and B​

Answer 1

HERE'S YOUR ANSWER

$\sin(a + b) = \frac{ \sqrt{3} }{2} \\ \\ = > \sin(a + b) = \sin60 \\ \\ = > a + b = 60 \\ \\ and \\ \cos(a - b) = 1\\ \\ = > \cos(a - b) = \cos0 \\ \\ = > a - b = 0 \ \\ \\ a + b + a - b = 60 + 0 \\ \\ = > 2a = 60 \\ \\ = > a = 30 \\ \\ and \\ b = 30$