Math, asked by sivakv1999, 4 months ago

sin (A + B) cos (A - B) + cos (A + B). sin (A - B) =​

Answers

Answered by MRROW
21

Answer:

REFER TO THE ATTACHED FILE FROM ME OF ANSWER

DON'T REPORT IT

MARK ME AS BRAINLEAST BRO

REFER TO THE

Attachments:
Answered by anannyashaw799
1

Answer:

1

Step-by-step explanation:

= Sin (A+B) Cos(A-B)+cos(A+B) Sin(A-B)

= Sin (A+B) Cos(90°-(A+B))+Cos(A+B) Sin(90°-(A+B))

= Sin(A+B) Sin(A+B)+Cos(A+B) Cos(A+B)

= Sin²(A+B)+Cos²(A+B)

=1 [because:sin²theta+cos²theta=1]

Similar questions