Math, asked by hiranyagangurde, 4 months ago

sin(a + b) cos(a-B) + cos(a + b)sin(a-B) =​

Answers

Answered by s115497aishika03187
1

Answer:

= [cos(a)*cos(b) + sin(a)*cos(b)] * cos(b) - [sin(a)*cos(b) - cos(a)*sin(b)] * sin(b)

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