Sin (A+B) / cosAcosB=tanAtanB
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Answered by
2
Step-by-step explanation:
Hi Alma,
sin(a+B) / cosacosB ? tana + tanB
sin(a+B) = sinacosB + cosasinB (identity)
sin(a+B) / cosacosB = (sinacosB + cosasinB) / (cosacosB)
= sinacosB/cosacosB + cosasinB/cosacosB
= sina/cosa + sinB/cosB
= tana + tanB
hope helpful to you ❤️ please mark has brilliant please ❤️
Answered by
0
Answer:
nice a tricky question the answer is written in itself it is a formula
Step-by-step explanation:
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