Sin a + b equal to 1 sin a minus b equal to one and half
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Solution :
Given
i ) sin(A+B) = 1
=> sin(A+B) = sin90°
=> A+B=90° ----( 1 )
ii ) Sin(A-B) = 1/2
=> sin(A-B) = sin30°
=> A-B=30°-----( 2 )
Add equations (1) and (2),
we get
2A = 120°
=> A = 60°
Substitute A = 60° in equation
( 1 ) , we get
60° + B = 90°
=> B = 90° - 60°
=> B = 30°
Therefore ,
A = 60° , B = 30°
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