Sin ( a + b ) /sen ( a − b ) = tan a +tan b /1 + tan a tan b
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= (sin A cos B + cos A sin B) / (cos A cos B − sin A sin B) (50) tan(A + B) = (tan A + tan B) / (1 − tan A tan B) Now if you replace B with −B, you have the formula for tan(A − B).
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