Sin(A+B)
sin(A-B)
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sin(A+B).sin(A−B)=[sin(A)cos(B)+cos(A)sin(B)][sin(A)cos(B)−cos(A)sin(B)]=sin2Acos2A−cos2Asin2A=sin2A[1−sin2B]−[1−sin2A]sin2B=sin2A−sin2Asin2B−sin2B+sin2Asin2B=sin2A−sin2BHence,theoptionCisthecorrectanswer.
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