Question

Sin (A – B) = Sin A Cos B – cos A sin B Cos (A – B) = cos A Cos B – sin A sin B Find sin 15° cos 15°​

Answer 1

Answer:

Sin (A – B) = Sin A Cos B – cos A sin B …(i)

Cos (A – B) = cos A Cos B – sin A sin B …(ii)

Let A = 45° B = 30° we get on substituting in (i)⇒ Sin(45° − 30°) = Sin 45° cos 30°

Sin 15° = 1√2∙√32−1√2∙12∴ Sin15°=√3−12√2(ii) A = 45° B = 30° in equation (ii) we getCos (45° − 30°) cos 45° cos 30° + sin 45° sin 30°Cos 15° -1√2∙√32+1√2∙12Cos 15° ⇒√3+12√2

Answer 2

Step-by-step explanation:

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