Question

sin (A-B) =SinA CosB -CosA SinB. find the value of sin15.​

Answer 1

Answer:

Sin 15° =

$\sqrt{3} - 1 \div 2 \sqrt{2}$

Step-by-step explanation:

sin15 = sin(45° - 30°)

sin45cos30 - cos45sin30

1/√2 × √3/2 - 1/√2 × 1/2

√3/2√2 - 1/2√2

= √3 - 1/2√2