Math, asked by Uttar5758, 10 months ago

sin(A+B)+sinA+sin(A-B) / cos(A+B)+cosA+cos(A-B) = tanA

Answers

Answered by sandy1816

6

Step-by-step explanation:

sin(A+B)+sin(A-B)+SinA/cos(A+B)+cos(A-B)+cosA

=2sinAcosB+sinA/2cosAcosB+cosA

=sinA(2cosB+1)/cosA(2cosB+1)

=sinA/cosA

=tanA

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