Math, asked by dhiraj348, 1 year ago

sin(A-B)/sinA.sinB=cotB-cotA

Answers

Answered by divprsw16

16

Sin(A-B)/SinA.SinB
= SinAcosB-sinBcosA/sinAsinB
=SinAcosB/sinAsinB - sinBcosA/sinAsinB
=cotB-cotA.

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