Question

Sin (A-B)=SinACosB-CosASinB

Answer 1

what you want plz describe

Answer 2

let A = 60 , B = 30

lhs = sin (A-B) = sin(60-30) = sin 30 =1/2
rhs = sinAcosB-cosAsinB

= sin60cos30 - cos60sin30
= √3/2 *√3/2 - 1/2*1/2
= 3/4 -1/4
=(3-1)/4
=2/4
=1/2
therefore 
lhs =rhs
sin(A-B) = sinAcosB - cosAsinB