Math, asked by kolisia, 6 months ago

sin(A+B) +son(A-B) ÷cos(A+B) +cos(A-B)

Answers

Answered by wasiakhtar23
0

Answer:

tanA

Step-by-step explanation:

sin(A+B) + sin (A- B ) / cos(A+ B) + cos (A- B)

= sinA cosB + cosA sinB + sinA cosB - cosA sinB/

cosA cosB - sinA sinB + cosA cosB + sinA sin B

= 2 sinA cosB / 2 cosA cosB

= sinA / cosA

= tan A

Answered by chetanakhairnar2000
0

Answer: PLEASE BRAINLIEST MY ANSWER

sin(A+B)+sin(A-B) / cos(A+B)+cos(A-B)  = tanA

Step-by-step explanation:

Q) sin(A+B) +sin(A-B) ÷cos(A+B) +cos(A-B)

⇒ [ sin(A+B)+sin(A-B) ] / [ cos(A+B)+cos(A-B) ]

⇒ [ (sinAcosB+cosAsinB) + (sinAcosB-cosAsinB) ]      /

     [ (cosAcosB-sinAsinB) + (cosAcosB+sinAsinB) ]

⇒ [ sinAcosB + cosAsinB + sinAcosB - cosAsinB ]    /

     [ cosAcosB - sinAsinB + cosAcosB + sinAsinB ]  

⇒ 2sinAcosB / 2cosAcosB

⇒ sinA / cosA

⇒ tanA

Similar questions