sin(A+B) +son(A-B) ÷cos(A+B) +cos(A-B)
Answers
Answered by
0
Answer:
tanA
Step-by-step explanation:
sin(A+B) + sin (A- B ) / cos(A+ B) + cos (A- B)
= sinA cosB + cosA sinB + sinA cosB - cosA sinB/
cosA cosB - sinA sinB + cosA cosB + sinA sin B
= 2 sinA cosB / 2 cosA cosB
= sinA / cosA
= tan A
Answered by
0
Answer: PLEASE BRAINLIEST MY ANSWER
sin(A+B)+sin(A-B) / cos(A+B)+cos(A-B) = tanA
Step-by-step explanation:
Q) sin(A+B) +sin(A-B) ÷cos(A+B) +cos(A-B)
⇒ [ sin(A+B)+sin(A-B) ] / [ cos(A+B)+cos(A-B) ]
⇒ [ (sinAcosB+cosAsinB) + (sinAcosB-cosAsinB) ] /
[ (cosAcosB-sinAsinB) + (cosAcosB+sinAsinB) ]
⇒ [ sinAcosB + cosAsinB + sinAcosB - cosAsinB ] /
[ cosAcosB - sinAsinB + cosAcosB + sinAsinB ]
⇒ 2sinAcosB / 2cosAcosB
⇒ sinA / cosA
⇒ tanA
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