Sin A÷ Cos (90-A) + tan(-A)÷tan(180-A) + Sec(180-A)÷Cosec(90-A) =1
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sin A/cos (90-A)+tanA/tan(180-A)+sec(180-A)/cosec(90-A)
=sinA/sinA+tanA/tan A+secA/secA
= 1+1+1
=3 answer
iamaman364:
Shubhamranjan52053, Prove it not solve it, this equation =1
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