Question

sin A- cos A+ 1 ÷
sin A+ cos A- 1 =
1 ÷ sec A - tan A
prove it

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Answer 1

Step-by-step explanation:

sinA-cosA+1/sinA+cosA-1

devide cosA in both numerator & denominator

tanA-1+secA/tanA+1-secA

={(tanA+secA)-1}(tanA-secA)/ (tanA-secA+1)(tanA-secA)

=tan²A-sec²A-tanA+secA/( tanA-secA+1)(tanA-secA)

=-1-tanA+secA/(tanA-secA+1)(tanA-secA)

=-(tanA-secA+1)/(tanA-secA+1)(tanA-secA)

=-1/tanA-secA

=1/secA-tanA