Question

sin A - cos A + 1 ÷ sin A + cos A -1 = cos A ÷ 1- sin A​

Answer 1

Answer:

hey mate here is your question..

$\frac{ \sin \alpha - \cos \alpha + 1 }{ \sin\alpha + \cos \alpha - 1 } = \frac{ \cos \alpha }{1 - \sin\alpha } \\ we \: know \: that \: \\ \sin ^{2} \alpha + \cos {}^{2} \alpha = 1 \\ \frac{ \sin \alpha - \cos \alpha + \sin {}^{2} \alpha + \cos {}^{2} \alpha }{ \sin\alpha + \cos\alpha - \sin {}^{2} \alpha - \cos {}^{2} \alpha } \\ \frac{ \sin \alpha - \cos\alpha ( \sin\alpha - \cos \alpha) }{ \sin\alpha + \cos \alpha ( - \sin\alpha - \cos \alpha) }$