sin A-cos A+1/ sin A+cosA-1=
sinA+1/cosA
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QUESTION :
- sin A-cos A+1/ sin A+cosA-1=
sinA+1/cosA
ANSWER :
- (sinA + 1 - cosA) / (cosA - 1 + sinA)
- Divide each term by cosA
- (tanA + secA - 1) / (1 - secA + tanA)
- [tanA + secA - ( [math]sec^2 A - tan^2 A [/math])] /
- ( 1 - secA + tanA)
- (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)
- tanA + secA
- (sinA / cosA )+ 1 / cosA
- (sinA + 1 )/ cosA
- Hence Proved
HOPE IT HELPS YOU
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