(sin A-Cos A)2 + 2 sin A cos A=1
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Answer:
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2sinAcosA−cosA−2sinA+1=0
2sinA(cosA−1)−1(cosA+−1)=0
(2sinA−1)(cosA−1)=0
sinA=
2
1
or cosA=1
sinA=sin30 or cosA=cos0
A=30
∘
or A=0
∘
Thus, A=0
∘
,30
∘
Answered by
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Step-by-step explanation:
w.k.t (a-b)^2=a^2+b^2-2ab
(sin A-cos A)^2+2 sin A cos A
=sin^2 A+cos^2 A-2 sin A cos A+2 sin A cos A
=sin ^2 A+cos^2 A
=1
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