Question

(sin A-Cos A)2 + 2 sin A cos A=1
Answer me..​

Answer 1

Answer:

0

2sinAcosA−cosA−2sinA+1=0

2sinA(cosA−1)−1(cosA+−1)=0

(2sinA−1)(cosA−1)=0

sinA=

2

1

or cosA=1

sinA=sin30 or cosA=cos0

A=30

∘

or A=0

∘

Thus, A=0

∘

,30

∘

Answer 2

Step-by-step explanation:

w.k.t (a-b)^2=a^2+b^2-2ab

(sin A-cos A)^2+2 sin A cos A

=sin^2 A+cos^2 A-2 sin A cos A+2 sin A cos A

=sin ^2 A+cos^2 A

=1