Question

(sin A + cos A)2 – 2 sin A cos A

Answer 1

Answer:

1

Step-by-step explanation:

Given--->

( SinA + CosA )² - 2SinA CosA

To find---> Value of given expression

Solution---> We have an identity as follows

( a + b )² = a² + b² + 2ab

We have a formula of trigonometery as follows

Sin²θ + Cos²θ = 1

Now returning to original problem

( SinA + CosA )² - 2SinA CosA

Applyig above identity , we get,

= ( SinA )² + ( CosA )² + 2SinA CosA - 2SinA CosA

- 2 SinA CosA and 2 SinA CosA cancel out each other and we get,

= Sin²A + Cos²A

Now applying above trigonometrical identity , we get,

= 1

Additional identity---->

1) 1 + tan²θ = Sec²θ

2) 1 + Cot²θ = Cosec²θ

3) ( a - b )² = a² + b² - 2ab

4) ( a + b )³ = a³ + b³ + 3ab ( a + b )

5) ( a - b )³ = a³ - b³ - 3ab ( a - b )

6) a³ + b³ = ( a + b ) ( a² + b² - ab )

7) a³ - b³ = ( a - b ) ( a² + b² + ab )

#Answerwithquality

#BAL

Answer 2

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1

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