(sin a+cos a)2+(sin a-cos a)2
Answers
Answered by
1
Answer:
2
Step-by-step explanation:
Considering the 2 after the brackets is the square term.
1. Opening the first bracket gives us
= sin^2a+cos^2a+2*sina*cosa
2. Now opening the second bracket gives us
= sin^2a+cos^2a-2*sina*cosa
3. As we know that sin^2a+cos^2a = 1, we get
= 1+2*sina*cosa+1-2*sina*cosa
= 2
Hope this helps!
Similar questions