Question

sin A+cos A= √2sin A then value of tan A is
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Answer 1

Answer:

tanA = √2 + 1

Step-by-step explanation:

$\sin( \alpha ) + \cos( \alpha ) = \sqrt{2} \sin( \alpha ) \\ = > \frac{ \sin( \alpha ) + \cos( \alpha ) }{ \sin( \alpha ) } = \sqrt{2} \\ = > \frac{ \sin( \alpha ) }{ \sin( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \alpha ) } = \sqrt{2} \\ = > 1 + \frac{1}{ \tan( \alpha ) } = \sqrt{2} \\ = > \frac{1}{ \tan( \alpha ) } = \sqrt{2} - 1 \\ = > \tan( \alpha ) = \frac{1}{ \sqrt{2} - 1} \\ = > \tan( \alpha ) = \sqrt{2} + 1$