Question

Sin A + cos A=root2
Plz help me with this

Answer 1

ur question is incomplete.

Answer 2

Answer:

2

Step-by-step explanation

SinA + CosA = √2 {Squaring on both sides}

(SinA + CosA)² = [√2]²

Sin²A + Cos²A + 2SinACosA = 2 (Sin²A + Cos²A = 1)

1 + 2SinACosA = 2

2SinACosA = 2-1

SinACosA = 1/2

# Take, TanA + CotA

SinA/CosA + CosA/SinA

Sin²A + Cos²A/ SinACosA

1/SinACosA (SinACosA = 1/2)

1/ 1/2

1× 2

2