[sin A +cos A] + [sin A- cos A] =2 PROVE IT
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Answer:
Correct option is
C
2
(sinA−cosA)
2
+(sinA+cosA)
2
=sin
2
A+cos
2
A−2sinAcosA+sin
2
A+cos
2
A+2sinAcosA
=sin
2
A+cos
2
A+sin
2
A+cos
2
A=1+1=2
(since, sin
2
A+cos
2
A=1)
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