Math, asked by anamikamishra67, 4 months ago

sin a+cos a/sin a- cos a+ sin a- cos a / sin a+ cos a​

Answers

Answered by hardiverma098
2

Answer:

sin a + cos a + sin a - cosa

----------------- -----------------

sin a - cos a sin a + cos a

= sin a2 + cos a2 + 2sin a cosa + sin a2 + cos a2 - 2sinacosa

------------------------------------------------

sin a2 - cos a2

= 1 + 1

--------

sin a2 - cosa2

= 2

---------

sin a2 - cosa2

Answered by Anonymous
50

Answer:

 \frac{sin \: a + cos \: a}{sin \: a -  \: cosa}  +  \frac{sin \: a -  \: cosa}{sin \: a +  \: cosa}

 \frac{(sin \: a +  \: cosa ) {}^{2} \:  + \:( sinaa \:   - \: cosa \:) {}^{2}   }{(sina  - \: cosa)( \: sina \: +  cosa)}

By using this identites

(a  + \: b) {}^{2}   = \: a {}^{2}  +  \: b {}^{2}   + \: 2ab

(a + b )(\: a - b) \ = a {}^{2}   - \: b {}^{2}

sin {}^{2} a +cos {}^{2} a + 2 \: sina \: cosa \: +  sin {}^{2} a \:   + cos {}^{2} a \ - 2sina \: cosa

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