Math, asked by AMIT1766, 1 year ago

Sin A + Cos A /sinA-Cos A + Sin A -Cos / sinA + Cos A = 2sec^2a/tan^2a-1

Answers

Answered by spiderman2019
1

Answer:

Step-by-step explanation:

(SinA+CosA)² + (SinA-CosA)²/ Sin²A - Cos²A

= 2/Sin²A - Cos²A

//take Cos²A common in the denominator.

= 2/ Cos²A(Sin²A/Cos²A - 1 )

= 2/Cos²A ( Tan²A - 1)

= 2Sec²A / Tan²A - 1

= R.H.S.

Hence Proved.

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