Math, asked by bhavanareddyr464, 1 year ago

(sin A + cos A) (tan A + cot A) = secA + cosec A​

Answers

Answered by sandy1816
2

Step-by-step explanation:

(sinA+cosA)(tanA+cotA)

=(sinA+cosA)(sinA/cosA+cosA/sinA)

=(sinA+cosA)(1/sinAcosA)

=sinA/sinAcosA+cosA/sinAcosA

=1/cosA + 1/sinA

=secA+cosecA

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