Sin A + Cos A the whole square is equal to 1 + 2 Sin A cos I
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= (Sin A + Cos A)²
= Sin²A + Cos²A + 2 (Sin A × Cos A)
(Identity - Sin²A + Cos²A = 1)
= 1 + 2 (Sin A × Cos A)
Hence Proved.
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☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
= Sin²A + Cos²A + 2 (Sin A × Cos A)
(Identity - Sin²A + Cos²A = 1)
= 1 + 2 (Sin A × Cos A)
Hence Proved.
________________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Answered by
1
here is ur answer.......
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