Sin A = cos A ,then find the value of cot(sq) A + 1/sin (sq)A
Math class 10
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drushasangwan:
I was about to ask the same q...
cool ! it was from cbse's official website
but i know the answer
Answers
Answered by
0
Answer: 2√2
Step-by-step explanation:
It is given that,
sin A=cos A
This is possible only when
A=45°
cot²A+1/sin A
= cosec² A/sin A
=1/sin³A
=1/sin³ 45°
=(√2)³
=2√2
Hope it helps you. Please mark as the brainliest...
procedure is right but not the ANS plz check the degree table again
Answered by
1
Answer: 1 + sec^2A
Step-by-step explanation: cot^2A + 1/ sin^2A
=Cos^2A/sin^2A + 1/sin^2A
=Cos^2A + 1/sin^2A
=Cos^2A +1/cos^2A ( sinA=cosA, Therefore, sin^2A=cos^2A)
=Cos^2A/cos^2A + 1/cos^2A
=1 + 1/cos^2A
=1 + sec^2A
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